fog

$f (x) = x^{2 D f : R} g (x) = \sqrt{x} D g : x \geq 0 f (g (x) = x D f o g = [x \in D g | g (x) \in D f] = [x \geq 0 | \sqrt{x} \in R] = [x \geq 0] g (f (x)) = x D g o f = [x \in D f | f (x) \in D g] = [x : R | x^{2} \in x \geq 0] m e n j a g v e t i n t e D g o f ?$

$\{x \in ℝ | x^{2} \geq 0\} = ℝ$

tack men varför grafen blir så

g(f(x)) = $\sqrt{x^{2}} = |x|$ .

Tack för svaret

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