Baser

$\mathit{u} = x_1{\mathit{v}}_{\mathbf{1}}+x_2{\mathit{v}}_2+x_3{\mathit{v}}_3= x_1\underline{\mathit{e}}\left[\begin{array}{c}1\\ 2\\ 1\end{array}\right]+x_2\underline{\mathit{e}}\left[\begin{array}{c}1\\ 0\\ 1\end{array}\right]+x_3\underline{\mathit{e}}\left[\begin{array}{c}-1\\ 1\\ 2\end{array}\right]=\underline{\mathit{e}}\left[\begin{array}{ccc}1& 1& -1\\ 2& 0& 1\\ 1& 1& 2\end{array}\right]\left[\begin{array}{c}{x}_1\\ x_2\\ x_3\end{array}\right]$  (1)

$\mathit{u} =\underline{\mathbf{ }\mathit{e}}\left[\begin{array}{c}2\\ 3\\ -4\end{array}\right]$  (2)

(1) = (2) ger… 

PATENTERAMERA skrev:

$\mathit{u} = x_1{\mathit{v}}_{\mathbf{1}}+x_2{\mathit{v}}_2+x_3{\mathit{v}}_3= x_1\underline{\mathit{e}}\left[\begin{array}{c}1\\ 2\\ 1\end{array}\right]+x_2\underline{\mathit{e}}\left[\begin{array}{c}1\\ 0\\ 1\end{array}\right]+x_3\underline{\mathit{e}}\left[\begin{array}{c}-1\\ 1\\ 2\end{array}\right]=\underline{\mathit{e}}\left[\begin{array}{ccc}1& 1& -1\\ 2& 0& 1\\ 1& 1& 2\end{array}\right]\left[\begin{array}{c}{x}_1\\ x_2\\ x_3\end{array}\right]$  (1)

$\mathit{u} =\underline{\mathbf{ }\mathit{e}}\left[\begin{array}{c}2\\ 3\\ -4\end{array}\right]$  (2)

(1) = (2) ger… 

Min beroendeekvation stämmer alltså, bara det att jag satte upp matrisen fel! Ska se vad jag får för svar!